next up previous
Next: Growth criteria Up: Cutting a manifold into Previous: Estimating for a string

Tubes that grow more or less exponentially

If the cross-section tex2html_wrap_inline1403 of a tube does not grow exponentially in one direction or the other, there is no hope that tex2html_wrap_inline1813 will be positive. The reason is that tex2html_wrap_inline1813 measures the exponential rate of decay of the heat kernel for the tube, and since the flow of heat along the tube is slow and no heat is lost, the temperature can't decay exponentially unless there is an exponential amount of material over which to distribute the heat.

On the other hand, if tex2html_wrap_inline1403 is growing exponentially with a certain minimum rate, and if it doesn't waver too much, then we can get a positive lower bound for tex2html_wrap_inline1813 . The bigger the minimum growth rate and the smaller the amount of wavering, the better the lower bound will be.

Lemma. Suppose that

where tex2html_wrap_inline1821 is piecewise tex2html_wrap_inline1617 and

displaymath1794

Then

Proof. Let

Then

so

Definition. If tex2html_wrap_inline1825 is measurable and satisfies

displaymath1799

for some piecewise tex2html_wrap_inline1617 function tex2html_wrap_inline1821 with

displaymath1800

then we say that f grows more or less exponentially, with rate a and factor K.

Proposition. Suppose for a cutting of M into tubes we can find constants a, K such that for almost all tex2html_wrap_inline1613 , tex2html_wrap_inline1655 grows more or less exponentially, with rate a and factor K. Then



Peter Doyle