Problem
Find
Solution
This function is the product of x2, which is easily differentiable, and ex, which is easily integrable. So integration by parts, with u = x2 and dv = ex dx, gives
This reduces the problem of finding the original integral to the simpler problem of finding
This problem is solved for us in Example 1 in Section 4.5:
So all together,
What if we had chosen something different for u and dv? Say we let u = ex, dv = x2 dx. Then we have du = ex dx,
and
This equation is true, but it doesn't simplify the problem, since integrating x3ex is as hard to solve as the original problem.