Separable Differential Equations: Quiz
Problem 4
Solve the following initial-value problem.
What is y(0)?
Answers, problem 4
Separate the variables and integrate both sides.
Therefore, y(1) = –2.5 = –(1/5 + C)
–1
=> C = 0.2
y(0) = –(0 + 0.2)
–1
= –5
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